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3a^2=a-1=0
We move all terms to the left:
3a^2-(a-1)=0
We get rid of parentheses
3a^2-a+1=0
We add all the numbers together, and all the variables
3a^2-1a+1=0
a = 3; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·3·1
Δ = -11
Delta is less than zero, so there is no solution for the equation
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